args="a b c"for arg in $argsdo #赋值 declare $arg=0 let $arg++donefor arg in $argsdo #提取 e
args="a b c"for arg in $argsdo #赋值 declare $arg=0 let $arg++donefor arg in $argsdo #提取 echo $arg: ${!arg}done参考:https://stackoverflow.com/questions/16553089/bash-dynamic-variable-names
