表结构：数据：需求：按照company_id不同分组，然后分别求出相同company_id相邻记录touch_time的差值SQL:select r1.company_id, r1.touch_time, r2.touc
表结构：
数据：
需求：
按照company_id不同分组，然后分别求出相同company_id相邻记录touch_time的差值
SQL:
select r1.company_id, r1.touch_time, r2.touch_time, r1.touch_time - r2.touch_time from (select (@rownum := @rownum + 1) as rownum, info.company_id, info.touch_time from sys_touch_info info, (select @rownum := 0) r where info.touch_time is not null order by info.company_id) r1 left join (select (@index := @index + 1) as rownum, info.company_id, info.touch_time from sys_touch_info info, (select @index := 0) r where info.touch_time is not null order by info.company_id) r2 on r1.company_id = r2.company_id and r1.rownum = r2.rownum - 1结果：
以上这篇Mysql 相邻两行记录某列的差值方法就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持编程圈。
